Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101011010011011 |
3 | 11001002201111212120112112 |
4 | 100212312303231122123 |
5 | 122144221213421412 |
6 | 2232135251102535 |
7 | 145310553231635 |
oct | 20466663553233 |
9 | 4032644776475 |
10 | 1141233342107 |
11 | 3aaaa3519231 |
12 | 1652188a1a4b |
13 | 83805527261 |
14 | 3d3437a3a55 |
15 | 1ea458ac722 |
hex | 109b6ced69b |
1141233342107 has 2 divisors, whose sum is σ = 1141233342108. Its totient is φ = 1141233342106.
The previous prime is 1141233342047. The next prime is 1141233342181. The reversal of 1141233342107 is 7012433321411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1141233342107 - 216 = 1141233276571 is a prime.
It is a super-2 number, since 2×11412333421072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1141233342187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616671053 + 570616671054.
It is an arithmetic number, because the mean of its divisors is an integer number (570616671054).
Almost surely, 21141233342107 is an apocalyptic number.
1141233342107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141233342107 is an equidigital number, since it uses as much as digits as its factorization.
1141233342107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 1141233342107 its reverse (7012433321411), we get a palindrome (8153666663518).
The spelling of 1141233342107 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-two thousand, one hundred seven".
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