Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101011001011111 |
3 | 11001002201111212120110022 |
4 | 100212312303231121133 |
5 | 122144221213421142 |
6 | 2232135251102355 |
7 | 145310553231521 |
oct | 20466663553137 |
9 | 4032644776408 |
10 | 1141233342047 |
11 | 3aaaa3519187 |
12 | 1652188a19bb |
13 | 83805527216 |
14 | 3d3437a3a11 |
15 | 1ea458ac6d2 |
hex | 109b6ced65f |
1141233342047 has 2 divisors, whose sum is σ = 1141233342048. Its totient is φ = 1141233342046.
The previous prime is 1141233342019. The next prime is 1141233342107. The reversal of 1141233342047 is 7402433321411.
It is a weak prime.
It is an emirp because it is prime and its reverse (7402433321411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1141233342047 - 28 = 1141233341791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141233341998 and 1141233342016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141233342017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616671023 + 570616671024.
It is an arithmetic number, because the mean of its divisors is an integer number (570616671024).
Almost surely, 21141233342047 is an apocalyptic number.
1141233342047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141233342047 is an equidigital number, since it uses as much as digits as its factorization.
1141233342047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 1141233342047 its reverse (7402433321411), we get a palindrome (8543666663458).
The spelling of 1141233342047 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-two thousand, forty-seven".
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