Base | Representation |
---|---|
bin | 10000100110110110110… |
… | …011101101111000101111 |
3 | 11001002201111212200012101 |
4 | 100212312303231320233 |
5 | 122144221214002142 |
6 | 2232135251115531 |
7 | 145310553240406 |
oct | 20466663557057 |
9 | 4032644780171 |
10 | 1141233344047 |
11 | 3aaaa351a735 |
12 | 1652188a2ba7 |
13 | 838055280c4 |
14 | 3d3437a463d |
15 | 1ea458ad0b7 |
hex | 109b6cede2f |
1141233344047 has 2 divisors, whose sum is σ = 1141233344048. Its totient is φ = 1141233344046.
The previous prime is 1141233343997. The next prime is 1141233344101. The reversal of 1141233344047 is 7404433321411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1141233344047 - 219 = 1141232819759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1141233343997 and 1141233344015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141233342047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570616672023 + 570616672024.
It is an arithmetic number, because the mean of its divisors is an integer number (570616672024).
Almost surely, 21141233344047 is an apocalyptic number.
1141233344047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141233344047 is an equidigital number, since it uses as much as digits as its factorization.
1141233344047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 37.
Adding to 1141233344047 its reverse (7404433321411), we get a palindrome (8545666665458).
It can be divided in two parts, 114 and 1233344047, that added together give a square (1233344161 = 351192).
The spelling of 1141233344047 in words is "one trillion, one hundred forty-one billion, two hundred thirty-three million, three hundred forty-four thousand, forty-seven".
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