Base | Representation |
---|---|
bin | 10101010000100011… |
… | …00001111101010111 |
3 | 1002110101202200020011 |
4 | 22220101201331113 |
5 | 141333223234143 |
6 | 5124302221051 |
7 | 552553525042 |
oct | 125021417527 |
9 | 32411680204 |
10 | 11413102423 |
11 | 4927442858 |
12 | 2266284787 |
13 | 10cb6a5958 |
14 | 7a3ac5c59 |
15 | 46be8ee9d |
hex | 2a8461f57 |
11413102423 has 2 divisors, whose sum is σ = 11413102424. Its totient is φ = 11413102422.
The previous prime is 11413102417. The next prime is 11413102427. The reversal of 11413102423 is 32420131411.
11413102423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11413102423 - 29 = 11413101911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11413102394 and 11413102403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11413102427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706551211 + 5706551212.
It is an arithmetic number, because the mean of its divisors is an integer number (5706551212).
Almost surely, 211413102423 is an apocalyptic number.
11413102423 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413102423 is an equidigital number, since it uses as much as digits as its factorization.
11413102423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11413102423 its reverse (32420131411), we get a palindrome (43833233834).
The spelling of 11413102423 in words is "eleven billion, four hundred thirteen million, one hundred two thousand, four hundred twenty-three".
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