Base | Representation |
---|---|
bin | 10101010000100011… |
… | …01011011010001011 |
3 | 1002110101211122022210 |
4 | 22220101223122023 |
5 | 141333231004011 |
6 | 5124303120203 |
7 | 552554045640 |
oct | 125021533213 |
9 | 32411748283 |
10 | 11413141131 |
11 | 4927469947 |
12 | 22662a3063 |
13 | 10cb6ba462 |
14 | 7a3ad5dc7 |
15 | 46be9b6a6 |
hex | 2a846b68b |
11413141131 has 64 divisors (see below), whose sum is σ = 18703319040. Its totient is φ = 6042677760.
The previous prime is 11413141111. The next prime is 11413141163. The reversal of 11413141131 is 13114131411.
It is not a de Polignac number, because 11413141131 - 25 = 11413141099 is a prime.
It is a super-2 number, since 2×114131411312 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a junction number, because it is equal to n+sod(n) for n = 11413141098 and 11413141107.
It is not an unprimeable number, because it can be changed into a prime (11413141111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6301216 + ... + 6303026.
It is an arithmetic number, because the mean of its divisors is an integer number (292239360).
Almost surely, 211413141131 is an apocalyptic number.
11413141131 is a deficient number, since it is larger than the sum of its proper divisors (7290177909).
11413141131 is a wasteful number, since it uses less digits than its factorization.
11413141131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2104.
The product of its digits is 144, while the sum is 21.
Adding to 11413141131 its reverse (13114131411), we get a palindrome (24527272542).
The spelling of 11413141131 in words is "eleven billion, four hundred thirteen million, one hundred forty-one thousand, one hundred thirty-one".
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