Base | Representation |
---|---|
bin | 1010011000010101010111… |
… | …0001110111110001000111 |
3 | 1111102002101020201021002101 |
4 | 2212011111301313301013 |
5 | 2443443131303223221 |
6 | 40135045303252531 |
7 | 2255400631614022 |
oct | 246052561676107 |
9 | 44362336637071 |
10 | 11413167242311 |
11 | 370032a40534a |
12 | 1343b4674a147 |
13 | 64a34598c123 |
14 | 2b658639a1b9 |
15 | 14bd3903cd91 |
hex | a6155c77c47 |
11413167242311 has 4 divisors (see below), whose sum is σ = 11419655684800. Its totient is φ = 11406678799824.
The previous prime is 11413167242293. The next prime is 11413167242317. The reversal of 11413167242311 is 11324276131411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11413167242311 - 221 = 11413165145159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11413167242317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3244218606 + ... + 3244222123.
It is an arithmetic number, because the mean of its divisors is an integer number (2854913921200).
Almost surely, 211413167242311 is an apocalyptic number.
11413167242311 is a deficient number, since it is larger than the sum of its proper divisors (6488442489).
11413167242311 is an equidigital number, since it uses as much as digits as its factorization.
11413167242311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6488442488.
The product of its digits is 24192, while the sum is 37.
The spelling of 11413167242311 in words is "eleven trillion, four hundred thirteen billion, one hundred sixty-seven million, two hundred forty-two thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •