1141323001333 has 2 divisors, whose sum is σ = 1141323001334. Its totient is φ = 1141323001332.

The previous prime is 1141323001319. The next prime is 1141323001367. The reversal of 1141323001333 is 3331003231411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1134689387524 + 6633613809 = 1065218^2 + 81447^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141323001333 - 2⁹ = 1141323000821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1141323001298 and 1141323001307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141323091333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570661500666 + 570661500667.

It is an arithmetic number, because the mean of its divisors is an integer number (570661500667).

Almost surely, 2^{1141323001333} is an apocalyptic number.

It is an amenable number.

1141323001333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141323001333 is an equidigital number, since it uses as much as digits as its factorization.

1141323001333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1141323001333 its reverse (3331003231411), we get a palindrome (4472326232744).

The spelling of 1141323001333 in words is "one trillion, one hundred forty-one billion, three hundred twenty-three million, one thousand, three hundred thirty-three".