Base | Representation |
---|---|
bin | 10101010000100100… |
… | …01100101111110011 |
3 | 1002110102002120122021 |
4 | 22220102030233303 |
5 | 141333244341213 |
6 | 5124310052311 |
7 | 552555155023 |
oct | 125022145763 |
9 | 32412076567 |
10 | 11413277683 |
11 | 49275524a5 |
12 | 226634a097 |
13 | 10cb737662 |
14 | 7a3b2da83 |
15 | 46bec6d8d |
hex | 2a848cbf3 |
11413277683 has 2 divisors, whose sum is σ = 11413277684. Its totient is φ = 11413277682.
The previous prime is 11413277653. The next prime is 11413277699. The reversal of 11413277683 is 38677231411.
It is a happy number.
11413277683 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413277683 is a prime.
It is not a weakly prime, because it can be changed into another prime (11413277653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706638841 + 5706638842.
It is an arithmetic number, because the mean of its divisors is an integer number (5706638842).
Almost surely, 211413277683 is an apocalyptic number.
11413277683 is a deficient number, since it is larger than the sum of its proper divisors (1).
11413277683 is an equidigital number, since it uses as much as digits as its factorization.
11413277683 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 169344, while the sum is 43.
The spelling of 11413277683 in words is "eleven billion, four hundred thirteen million, two hundred seventy-seven thousand, six hundred eighty-three".
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