Base | Representation |
---|---|
bin | 10101010000100100… |
… | …10100101111101011 |
3 | 1002110102011020120121 |
4 | 22220102110233223 |
5 | 141333301413233 |
6 | 5124310504111 |
7 | 552555352363 |
oct | 125022245753 |
9 | 32412136517 |
10 | 11413310443 |
11 | 4927575077 |
12 | 2266365037 |
13 | 10cb749542 |
14 | 7a3b3b9a3 |
15 | 46bed192d |
hex | 2a8494beb |
11413310443 has 4 divisors (see below), whose sum is σ = 11461065120. Its totient is φ = 11365555768.
The previous prime is 11413310437. The next prime is 11413310459. The reversal of 11413310443 is 34401331411.
It is a happy number.
11413310443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11413310443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11413310423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23876980 + ... + 23877457.
It is an arithmetic number, because the mean of its divisors is an integer number (2865266280).
Almost surely, 211413310443 is an apocalyptic number.
11413310443 is a deficient number, since it is larger than the sum of its proper divisors (47754677).
11413310443 is an equidigital number, since it uses as much as digits as its factorization.
11413310443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47754676.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11413310443 its reverse (34401331411), we get a palindrome (45814641854).
The spelling of 11413310443 in words is "eleven billion, four hundred thirteen million, three hundred ten thousand, four hundred forty-three".
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