Base | Representation |
---|---|
bin | 10000100110111100110… |
… | …001011101001000110101 |
3 | 11001002222111011202222201 |
4 | 100212330301131020311 |
5 | 122144422323230303 |
6 | 2232153224024501 |
7 | 145313206645021 |
oct | 20467461351065 |
9 | 4032874152881 |
10 | 1141333414453 |
11 | 400044a5a051 |
12 | 165246302131 |
13 | 8382019496b |
14 | 3d352bb3381 |
15 | 1ea4e57881d |
hex | 109bcc5d235 |
1141333414453 has 2 divisors, whose sum is σ = 1141333414454. Its totient is φ = 1141333414452.
The previous prime is 1141333414363. The next prime is 1141333414519. The reversal of 1141333414453 is 3544143331411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 940321968804 + 201011445649 = 969702^2 + 448343^2 .
It is a cyclic number.
It is not a de Polignac number, because 1141333414453 - 217 = 1141333283381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1141333414553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570666707226 + 570666707227.
It is an arithmetic number, because the mean of its divisors is an integer number (570666707227).
Almost surely, 21141333414453 is an apocalyptic number.
It is an amenable number.
1141333414453 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141333414453 is an equidigital number, since it uses as much as digits as its factorization.
1141333414453 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 37.
Adding to 1141333414453 its reverse (3544143331411), we get a palindrome (4685476745864).
The spelling of 1141333414453 in words is "one trillion, one hundred forty-one billion, three hundred thirty-three million, four hundred fourteen thousand, four hundred fifty-three".
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