Base | Representation |
---|---|
bin | 10000100110111101011… |
… | …010110000110110011111 |
3 | 11001010000020112221002211 |
4 | 100212331122300312133 |
5 | 122144433111234403 |
6 | 2232154252101251 |
7 | 145313400665311 |
oct | 20467532606637 |
9 | 4033006487084 |
10 | 1141344243103 |
11 | 400050085849 |
12 | 165249a64827 |
13 | 838224b674c |
14 | 3d3543d17b1 |
15 | 1ea504b706d |
hex | 109bd6b0d9f |
1141344243103 has 8 divisors (see below), whose sum is σ = 1201608987120. Its totient is φ = 1081098898560.
The previous prime is 1141344243077. The next prime is 1141344243139. The reversal of 1141344243103 is 3013424431411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1141344243103 - 213 = 1141344234911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1141344843103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4729018 + ... + 4964503.
It is an arithmetic number, because the mean of its divisors is an integer number (150201123390).
Almost surely, 21141344243103 is an apocalyptic number.
1141344243103 is a deficient number, since it is larger than the sum of its proper divisors (60264744017).
1141344243103 is an equidigital number, since it uses as much as digits as its factorization.
1141344243103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9699737.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1141344243103 its reverse (3013424431411), we get a palindrome (4154768674514).
The spelling of 1141344243103 in words is "one trillion, one hundred forty-one billion, three hundred forty-four million, two hundred forty-three thousand, one hundred three".
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