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11413535431 is a prime number
BaseRepresentation
bin10101010000100110…
…01011101011000111
31002110102120200012111
422220103023223013
5141333331113211
65124315401451
7552560310334
oct125023135307
932412520174
1011413535431
114927709111
122266453287
1310cb7c7a7c
147a3b9998b
1546c028421
hex2a84cbac7

11413535431 has 2 divisors, whose sum is σ = 11413535432. Its totient is φ = 11413535430.

The previous prime is 11413535417. The next prime is 11413535437. The reversal of 11413535431 is 13453531411.

11413535431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11413535431 - 27 = 11413535303 is a prime.

It is a super-2 number, since 2×114135354312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11413535393 and 11413535402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11413535437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706767715 + 5706767716.

It is an arithmetic number, because the mean of its divisors is an integer number (5706767716).

Almost surely, 211413535431 is an apocalyptic number.

11413535431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11413535431 is an equidigital number, since it uses as much as digits as its factorization.

11413535431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10800, while the sum is 31.

The spelling of 11413535431 in words is "eleven billion, four hundred thirteen million, five hundred thirty-five thousand, four hundred thirty-one".