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11414000403 = 321397555559
BaseRepresentation
bin10101010000101001…
…11101001100010011
31002110110110022000200
422220110331030103
5141333441003103
65124333350243
7552564255051
oct125024751423
932413408020
1011414000403
1149279a6493
122266638383
1310cb92b5c0
147a3c7b1d1
1546c0bb0a3
hex2a853d313

11414000403 has 12 divisors (see below), whose sum is σ = 17755111920. Its totient is φ = 7024000176.

The previous prime is 11414000393. The next prime is 11414000441. The reversal of 11414000403 is 30400041411.

It is not a de Polignac number, because 11414000403 - 24 = 11414000387 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11414000443) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 48777663 + ... + 48777896.

It is an arithmetic number, because the mean of its divisors is an integer number (1479592660).

Almost surely, 211414000403 is an apocalyptic number.

11414000403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11414000403 is a deficient number, since it is larger than the sum of its proper divisors (6341111517).

11414000403 is a wasteful number, since it uses less digits than its factorization.

11414000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97555578 (or 97555575 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 11414000403 its reverse (30400041411), we get a palindrome (41814041814).

It can be divided in two parts, 11 and 414000403, that added together give a palindrome (414000414).

The spelling of 11414000403 in words is "eleven billion, four hundred fourteen million, four hundred three", and thus it is an aban number.

Divisors: 1 3 9 13 39 117 97555559 292666677 878000031 1268222267 3804666801 11414000403