Base | Representation |
---|---|
bin | 110101001001101000… |
… | …1101111011001101111 |
3 | 101220121121122100202100 |
4 | 1222103101233121233 |
5 | 3332224323113210 |
6 | 124234001230143 |
7 | 11150332266102 |
oct | 1522321573157 |
9 | 356547570670 |
10 | 114140051055 |
11 | 444520a0808 |
12 | 1a155332353 |
13 | a9c0145c64 |
14 | 574ad92739 |
15 | 2e807d45c0 |
hex | 1a9346f66f |
114140051055 has 24 divisors (see below), whose sum is σ = 197937988560. Its totient is φ = 60845391360.
The previous prime is 114140050963. The next prime is 114140051087. The reversal of 114140051055 is 550150041411.
114140051055 is a `hidden beast` number, since 1 + 1 + 4 + 140 + 0 + 510 + 5 + 5 = 666.
It is not a de Polignac number, because 114140051055 - 218 = 114139788911 is a prime.
It is a super-2 number, since 2×1141400510552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 515785 + ... + 703074.
It is an arithmetic number, because the mean of its divisors is an integer number (8247416190).
Almost surely, 2114140051055 is an apocalyptic number.
114140051055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114140051055 is a deficient number, since it is larger than the sum of its proper divisors (83797937505).
114140051055 is a wasteful number, since it uses less digits than its factorization.
114140051055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1220951 (or 1220948 counting only the distinct ones).
The product of its (nonzero) digits is 2000, while the sum is 27.
Adding to 114140051055 its reverse (550150041411), we get a palindrome (664290092466).
The spelling of 114140051055 in words is "one hundred fourteen billion, one hundred forty million, fifty-one thousand, fifty-five".
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