11414010403 has 4 divisors (see below), whose sum is σ = 11415473928. Its totient is φ = 11412546880.

The previous prime is 11414010401. The next prime is 11414010451. The reversal of 11414010403 is 30401041411.

11414010403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11414010403 - 2¹ = 11414010401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11414010401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720001 + ... + 735682.

It is an arithmetic number, because the mean of its divisors is an integer number (2853868482).

Almost surely, 2^11414010403 is an apocalyptic number.

11414010403 is a deficient number, since it is larger than the sum of its proper divisors (1463525).

11414010403 is an equidigital number, since it uses as much as digits as its factorization.

11414010403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1463524.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11414010403 its reverse (30401041411), we get a palindrome (41815051814).

It can be divided in two parts, 11 and 414010403, that added together give a palindrome (414010414).

The spelling of 11414010403 in words is "eleven billion, four hundred fourteen million, ten thousand, four hundred three".