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11414012431 is a prime number
BaseRepresentation
bin10101010000101010…
…00000001000001111
31002110110110220112011
422220111000020033
5141333441344211
65124333522051
7552564335113
oct125025001017
932413426464
1011414012431
114927a04528
122266643327
1310cb933c13
147a3c81743
1546c0be921
hex2a854020f

11414012431 has 2 divisors, whose sum is σ = 11414012432. Its totient is φ = 11414012430.

The previous prime is 11414012429. The next prime is 11414012471. The reversal of 11414012431 is 13421041411.

It is a weak prime.

It is an emirp because it is prime and its reverse (13421041411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11414012431 - 21 = 11414012429 is a prime.

It is a super-2 number, since 2×114140124312 (a number of 21 digits) contains 22 as substring.

Together with 11414012429, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11414012471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707006215 + 5707006216.

It is an arithmetic number, because the mean of its divisors is an integer number (5707006216).

Almost surely, 211414012431 is an apocalyptic number.

11414012431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11414012431 is an equidigital number, since it uses as much as digits as its factorization.

11414012431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 11414012431 its reverse (13421041411), we get a palindrome (24835053842).

The spelling of 11414012431 in words is "eleven billion, four hundred fourteen million, twelve thousand, four hundred thirty-one".