11414114113 has 4 divisors (see below), whose sum is σ = 11910379968. Its totient is φ = 10917848260.

The previous prime is 11414114081. The next prime is 11414114137. The reversal of 11414114113 is 31141141411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31141141411 = 2011 ⋅15485401.

It is a cyclic number.

It is not a de Polignac number, because 11414114113 - 2⁵ = 11414114081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11414114183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248132893 + ... + 248132938.

It is an arithmetic number, because the mean of its divisors is an integer number (2977594992).

Almost surely, 2^11414114113 is an apocalyptic number.

It is an amenable number.

11414114113 is a deficient number, since it is larger than the sum of its proper divisors (496265855).

11414114113 is an equidigital number, since it uses as much as digits as its factorization.

11414114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496265854.

The product of its digits is 192, while the sum is 22.

Adding to 11414114113 its reverse (31141141411), we get a palindrome (42555255524).

The spelling of 11414114113 in words is "eleven billion, four hundred fourteen million, one hundred fourteen thousand, one hundred thirteen".