Base | Representation |
---|---|
bin | 110101001001101100… |
… | …1001011100101000001 |
3 | 101220121202022110020001 |
4 | 1222103121023211001 |
5 | 3332230323021343 |
6 | 124234111120001 |
7 | 11150355001333 |
oct | 1522331134501 |
9 | 356552273201 |
10 | 114142001473 |
11 | 44453203125 |
12 | 1a155b13001 |
13 | a9c0679956 |
14 | 574b33d453 |
15 | 2e80a6c44d |
hex | 1a9364b941 |
114142001473 has 2 divisors, whose sum is σ = 114142001474. Its totient is φ = 114142001472.
The previous prime is 114142001431. The next prime is 114142001509. The reversal of 114142001473 is 374100241411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78821685504 + 35320315969 = 280752^2 + 187937^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114142001473 is a prime.
It is not a weakly prime, because it can be changed into another prime (114142001773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071000736 + 57071000737.
It is an arithmetic number, because the mean of its divisors is an integer number (57071000737).
Almost surely, 2114142001473 is an apocalyptic number.
It is an amenable number.
114142001473 is a deficient number, since it is larger than the sum of its proper divisors (1).
114142001473 is an equidigital number, since it uses as much as digits as its factorization.
114142001473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 114142001473 its reverse (374100241411), we get a palindrome (488242242884).
The spelling of 114142001473 in words is "one hundred fourteen billion, one hundred forty-two million, one thousand, four hundred seventy-three".
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