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114142001473 is a prime number
BaseRepresentation
bin110101001001101100…
…1001011100101000001
3101220121202022110020001
41222103121023211001
53332230323021343
6124234111120001
711150355001333
oct1522331134501
9356552273201
10114142001473
1144453203125
121a155b13001
13a9c0679956
14574b33d453
152e80a6c44d
hex1a9364b941

114142001473 has 2 divisors, whose sum is σ = 114142001474. Its totient is φ = 114142001472.

The previous prime is 114142001431. The next prime is 114142001509. The reversal of 114142001473 is 374100241411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78821685504 + 35320315969 = 280752^2 + 187937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114142001473 is a prime.

It is not a weakly prime, because it can be changed into another prime (114142001773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071000736 + 57071000737.

It is an arithmetic number, because the mean of its divisors is an integer number (57071000737).

Almost surely, 2114142001473 is an apocalyptic number.

It is an amenable number.

114142001473 is a deficient number, since it is larger than the sum of its proper divisors (1).

114142001473 is an equidigital number, since it uses as much as digits as its factorization.

114142001473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 114142001473 its reverse (374100241411), we get a palindrome (488242242884).

The spelling of 114142001473 in words is "one hundred fourteen billion, one hundred forty-two million, one thousand, four hundred seventy-three".