Base | Representation |
---|---|
bin | 110101001001101100… |
… | …1001011100100010111 |
3 | 101220121202022110011111 |
4 | 1222103121023210113 |
5 | 3332230323021211 |
6 | 124234111115451 |
7 | 11150355001243 |
oct | 1522331134427 |
9 | 356552273144 |
10 | 114142001431 |
11 | 44453203097 |
12 | 1a155b12b87 |
13 | a9c0679923 |
14 | 574b33d423 |
15 | 2e80a6c421 |
hex | 1a9364b917 |
114142001431 has 2 divisors, whose sum is σ = 114142001432. Its totient is φ = 114142001430.
The previous prime is 114142001381. The next prime is 114142001473. The reversal of 114142001431 is 134100241411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114142001431 - 213 = 114141993239 is a prime.
It is a super-3 number, since 3×1141420014313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114142001131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071000715 + 57071000716.
It is an arithmetic number, because the mean of its divisors is an integer number (57071000716).
Almost surely, 2114142001431 is an apocalyptic number.
114142001431 is a deficient number, since it is larger than the sum of its proper divisors (1).
114142001431 is an equidigital number, since it uses as much as digits as its factorization.
114142001431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 114142001431 its reverse (134100241411), we get a palindrome (248242242842).
The spelling of 114142001431 in words is "one hundred fourteen billion, one hundred forty-two million, one thousand, four hundred thirty-one".
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