114142131031 has 2 divisors, whose sum is σ = 114142131032. Its totient is φ = 114142131030.

The previous prime is 114142131007. The next prime is 114142131049. The reversal of 114142131031 is 130131241411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114142131031 - 2¹⁵ = 114142098263 is a prime.

It is a super-2 number, since 2×114142131031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114142130993 and 114142131011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114142131071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57071065515 + 57071065516.

It is an arithmetic number, because the mean of its divisors is an integer number (57071065516).

Almost surely, 2^114142131031 is an apocalyptic number.

114142131031 is a deficient number, since it is larger than the sum of its proper divisors (1).

114142131031 is an equidigital number, since it uses as much as digits as its factorization.

114142131031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 114142131031 its reverse (130131241411), we get a palindrome (244273372442).

The spelling of 114142131031 in words is "one hundred fourteen billion, one hundred forty-two million, one hundred thirty-one thousand, thirty-one".