Base | Representation |
---|---|
bin | 10101010000101100… |
… | …01000111000000011 |
3 | 1002110111001001021011 |
4 | 22220112020320003 |
5 | 141334030413103 |
6 | 5124344141351 |
7 | 552600015616 |
oct | 125026107003 |
9 | 32414031234 |
10 | 11414310403 |
11 | 4928098391 |
12 | 2266767857 |
13 | 10cba09732 |
14 | 7a3d1c17d |
15 | 46c12cd6d |
hex | 2a8588e03 |
11414310403 has 2 divisors, whose sum is σ = 11414310404. Its totient is φ = 11414310402.
The previous prime is 11414310353. The next prime is 11414310433. The reversal of 11414310403 is 30401341411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11414310403 - 217 = 11414179331 is a prime.
It is not a weakly prime, because it can be changed into another prime (11414310433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707155201 + 5707155202.
It is an arithmetic number, because the mean of its divisors is an integer number (5707155202).
Almost surely, 211414310403 is an apocalyptic number.
11414310403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414310403 is an equidigital number, since it uses as much as digits as its factorization.
11414310403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 11414310403 its reverse (30401341411), we get a palindrome (41815651814).
The spelling of 11414310403 in words is "eleven billion, four hundred fourteen million, three hundred ten thousand, four hundred three".
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