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1141431230207 is a prime number
BaseRepresentation
bin10000100111000010100…
…110100101111011111111
311001010020022020022222102
4100213002212211323333
5122200122343331312
62232211040335315
7145315505242112
oct20470246457377
94033208208872
101141431230207
11400095199514
1216527301453b
13838375221c8
143d361b96579
151ea57e4aec2
hex109c29a5eff

1141431230207 has 2 divisors, whose sum is σ = 1141431230208. Its totient is φ = 1141431230206.

The previous prime is 1141431230131. The next prime is 1141431230221. The reversal of 1141431230207 is 7020321341411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1141431230207 - 224 = 1141414452991 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1141431230207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1141431230227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570715615103 + 570715615104.

It is an arithmetic number, because the mean of its divisors is an integer number (570715615104).

Almost surely, 21141431230207 is an apocalyptic number.

1141431230207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141431230207 is an equidigital number, since it uses as much as digits as its factorization.

1141431230207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 1141431230207 its reverse (7020321341411), we get a palindrome (8161752571618).

The spelling of 1141431230207 in words is "one trillion, one hundred forty-one billion, four hundred thirty-one million, two hundred thirty thousand, two hundred seven".