Base | Representation |
---|---|
bin | 10101010000101100… |
… | …10000111010101101 |
3 | 1002110111002201110002 |
4 | 22220112100322231 |
5 | 141334032441331 |
6 | 5124344554045 |
7 | 552600213632 |
oct | 125026207255 |
9 | 32414081402 |
10 | 11414343341 |
11 | 4928110105 |
12 | 2266782925 |
13 | 10cba1b71b |
14 | 7a3d2a189 |
15 | 46c1379cb |
hex | 2a8590ead |
11414343341 has 2 divisors, whose sum is σ = 11414343342. Its totient is φ = 11414343340.
The previous prime is 11414343323. The next prime is 11414343349. The reversal of 11414343341 is 14334341411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8428158025 + 2986185316 = 91805^2 + 54646^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11414343341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11414343349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5707171670 + 5707171671.
It is an arithmetic number, because the mean of its divisors is an integer number (5707171671).
Almost surely, 211414343341 is an apocalyptic number.
It is an amenable number.
11414343341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11414343341 is an equidigital number, since it uses as much as digits as its factorization.
11414343341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 29.
Adding to 11414343341 its reverse (14334341411), we get a palindrome (25748684752).
The spelling of 11414343341 in words is "eleven billion, four hundred fourteen million, three hundred forty-three thousand, three hundred forty-one".
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