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11414343340 = 225570717167
BaseRepresentation
bin10101010000101100…
…10000111010101100
31002110111002201110001
422220112100322230
5141334032441330
65124344554044
7552600213631
oct125026207254
932414081401
1011414343340
114928110104
122266782924
1310cba1b71a
147a3d2a188
1546c1379ca
hex2a8590eac

11414343340 has 12 divisors (see below), whose sum is σ = 23970121056. Its totient is φ = 4565737328.

The previous prime is 11414343323. The next prime is 11414343341. The reversal of 11414343340 is 4334341411.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 11414343299 and 11414343308.

It is not an unprimeable number, because it can be changed into a prime (11414343341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285358564 + ... + 285358603.

It is an arithmetic number, because the mean of its divisors is an integer number (1997510088).

Almost surely, 211414343340 is an apocalyptic number.

11414343340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11414343340 is an abundant number, since it is smaller than the sum of its proper divisors (12555777716).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11414343340 is a wasteful number, since it uses less digits than its factorization.

11414343340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 570717176 (or 570717174 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 11414343340 its reverse (4334341411), we get a palindrome (15748684751).

The spelling of 11414343340 in words is "eleven billion, four hundred fourteen million, three hundred forty-three thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 570717167 1141434334 2282868668 2853585835 5707171670 11414343340