114150432431 has 4 divisors (see below), whose sum is σ = 130457637072. Its totient is φ = 97843227792.

The previous prime is 114150432421. The next prime is 114150432467. The reversal of 114150432431 is 134234051411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 134234051411 = 6011 ⋅22331401.

It is a cyclic number.

It is not a de Polignac number, because 114150432431 - 2¹⁰ = 114150431407 is a prime.

It is a super-3 number, since 3×114150432431³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 114150432394 and 114150432403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114150432421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8153602310 + ... + 8153602323.

It is an arithmetic number, because the mean of its divisors is an integer number (32614409268).

Almost surely, 2^114150432431 is an apocalyptic number.

114150432431 is a deficient number, since it is larger than the sum of its proper divisors (16307204641).

114150432431 is an equidigital number, since it uses as much as digits as its factorization.

114150432431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16307204640.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 114150432431 its reverse (134234051411), we get a palindrome (248384483842).

The spelling of 114150432431 in words is "one hundred fourteen billion, one hundred fifty million, four hundred thirty-two thousand, four hundred thirty-one".