11417095121933 has 2 divisors, whose sum is σ = 11417095121934. Its totient is φ = 11417095121932.

The previous prime is 11417095121903. The next prime is 11417095121963. The reversal of 11417095121933 is 33912159071411.

11417095121933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (11417095121903) and next prime (11417095121963).

It can be written as a sum of positive squares in only one way, i.e., 9430537362724 + 1986557759209 = 3070918^2 + 1409453^2 .

It is a cyclic number.

It is not a de Polignac number, because 11417095121933 - 2⁴⁰ = 10317583494157 is a prime.

It is a super-2 number, since 2×11417095121933² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11417095121903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5708547560966 + 5708547560967.

It is an arithmetic number, because the mean of its divisors is an integer number (5708547560967).

Almost surely, 2^{11417095121933} is an apocalyptic number.

It is an amenable number.

11417095121933 is a deficient number, since it is larger than the sum of its proper divisors (1).

11417095121933 is an equidigital number, since it uses as much as digits as its factorization.

11417095121933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 204120, while the sum is 47.

The spelling of 11417095121933 in words is "eleven trillion, four hundred seventeen billion, ninety-five million, one hundred twenty-one thousand, nine hundred thirty-three".