Base | Representation |
---|---|
bin | 10101010001011000… |
… | …10100001111000111 |
3 | 1002110212222102011101 |
4 | 22220230110033013 |
5 | 141342022432403 |
6 | 5125112520531 |
7 | 553000311313 |
oct | 125054241707 |
9 | 32425872141 |
10 | 11420124103 |
11 | 49303a92a3 |
12 | 22686b0147 |
13 | 10ccc939ab |
14 | 7a49d2b43 |
15 | 46c8ca71d |
hex | 2a8b143c7 |
11420124103 has 2 divisors, whose sum is σ = 11420124104. Its totient is φ = 11420124102.
The previous prime is 11420124077. The next prime is 11420124143. The reversal of 11420124103 is 30142102411.
It is a weak prime.
It is an emirp because it is prime and its reverse (30142102411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11420124103 - 213 = 11420115911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11420124143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710062051 + 5710062052.
It is an arithmetic number, because the mean of its divisors is an integer number (5710062052).
Almost surely, 211420124103 is an apocalyptic number.
11420124103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11420124103 is an equidigital number, since it uses as much as digits as its factorization.
11420124103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11420124103 its reverse (30142102411), we get a palindrome (41562226514).
The spelling of 11420124103 in words is "eleven billion, four hundred twenty million, one hundred twenty-four thousand, one hundred three".
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