Base | Representation |
---|---|
bin | 10101010001011000… |
… | …10100001111101111 |
3 | 1002110212222102012212 |
4 | 22220230110033233 |
5 | 141342022433033 |
6 | 5125112521035 |
7 | 553000311401 |
oct | 125054241757 |
9 | 32425872185 |
10 | 11420124143 |
11 | 49303a932a |
12 | 22686b017b |
13 | 10ccc93a0c |
14 | 7a49d2b71 |
15 | 46c8ca748 |
hex | 2a8b143ef |
11420124143 has 2 divisors, whose sum is σ = 11420124144. Its totient is φ = 11420124142.
The previous prime is 11420124103. The next prime is 11420124179. The reversal of 11420124143 is 34142102411.
It is a strong prime.
It is an emirp because it is prime and its reverse (34142102411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11420124143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11420124103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710062071 + 5710062072.
It is an arithmetic number, because the mean of its divisors is an integer number (5710062072).
Almost surely, 211420124143 is an apocalyptic number.
11420124143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11420124143 is an equidigital number, since it uses as much as digits as its factorization.
11420124143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 11420124143 its reverse (34142102411), we get a palindrome (45562226554).
The spelling of 11420124143 in words is "eleven billion, four hundred twenty million, one hundred twenty-four thousand, one hundred forty-three".
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