11420131 has 2 divisors, whose sum is σ = 11420132. Its totient is φ = 11420130.

The previous prime is 11420111. The next prime is 11420173. The reversal of 11420131 is 13102411.

11420131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11420131 - 2⁹ = 11419619 is a prime.

It is a super-2 number, since 2×11420131² = 260838784114322, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11420111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710065 + 5710066.

It is an arithmetic number, because the mean of its divisors is an integer number (5710066).

Almost surely, 2^11420131 is an apocalyptic number.

11420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11420131 is an equidigital number, since it uses as much as digits as its factorization.

11420131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 11420131 is about 3379.3684321186. The cubic root of 11420131 is about 225.1941106791.

Adding to 11420131 its reverse (13102411), we get a palindrome (24522542).

The spelling of 11420131 in words is "eleven million, four hundred twenty thousand, one hundred thirty-one".