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11420173 is a prime number
BaseRepresentation
bin101011100100…
…001000001101
3210111012112101
4223210020031
510410421143
61044435101
7166032652
oct53441015
923435471
1011420173
1164a0166
1239a8a91
13249b0cb
141733c29
151008b4d
hexae420d

11420173 has 2 divisors, whose sum is σ = 11420174. Its totient is φ = 11420172.

The previous prime is 11420131. The next prime is 11420177. The reversal of 11420173 is 37102411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9972964 + 1447209 = 3158^2 + 1203^2 .

It is a cyclic number.

It is not a de Polignac number, because 11420173 - 217 = 11289101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11420173.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11420177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5710086 + 5710087.

It is an arithmetic number, because the mean of its divisors is an integer number (5710087).

Almost surely, 211420173 is an apocalyptic number.

It is an amenable number.

11420173 is a deficient number, since it is larger than the sum of its proper divisors (1).

11420173 is an equidigital number, since it uses as much as digits as its factorization.

11420173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

The square root of 11420173 is about 3379.3746462918. The cubic root of 11420173 is about 225.1943867455.

Adding to 11420173 its reverse (37102411), we get a palindrome (48522584).

The spelling of 11420173 in words is "eleven million, four hundred twenty thousand, one hundred seventy-three".