Base | Representation |
---|---|
bin | 10101010001011010… |
… | …01001001100101011 |
3 | 1002110220101102201220 |
4 | 22220231021030223 |
5 | 141342101403120 |
6 | 5125121313123 |
7 | 553002203625 |
oct | 125055111453 |
9 | 32426342656 |
10 | 11420341035 |
11 | 4930537284 |
12 | 22687957a3 |
13 | 110003b65c |
14 | 7a4a4bc15 |
15 | 46c91eb40 |
hex | 2a8b4932b |
11420341035 has 8 divisors (see below), whose sum is σ = 18272545680. Its totient is φ = 6090848544.
The previous prime is 11420341033. The next prime is 11420341043. The reversal of 11420341035 is 53014302411.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11420341035 - 21 = 11420341033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11420340996 and 11420341014.
It is not an unprimeable number, because it can be changed into a prime (11420341033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 380678020 + ... + 380678049.
It is an arithmetic number, because the mean of its divisors is an integer number (2284068210).
Almost surely, 211420341035 is an apocalyptic number.
11420341035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11420341035 is a deficient number, since it is larger than the sum of its proper divisors (6852204645).
11420341035 is an equidigital number, since it uses as much as digits as its factorization.
11420341035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 761356077.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 11420341035 its reverse (53014302411), we get a palindrome (64434643446).
The spelling of 11420341035 in words is "eleven billion, four hundred twenty million, three hundred forty-one thousand, thirty-five".
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