Base | Representation |
---|---|
bin | 11001111101111010001010… |
… | …111110110011011101000111 |
3 | 112222100221101111112212212020 |
4 | 121331322022332303131013 |
5 | 104432120342100321020 |
6 | 1042521142111454223 |
7 | 33025035024651042 |
oct | 3175721276633507 |
9 | 488327344485766 |
10 | 114205512120135 |
11 | 33431316295447 |
12 | 10985962b27373 |
13 | 4b956c23845b7 |
14 | 202b80d451c59 |
15 | d30b32a07c40 |
hex | 67de8afb3747 |
114205512120135 has 64 divisors (see below), whose sum is σ = 184196263680000. Its totient is φ = 60421572771840.
The previous prime is 114205512120083. The next prime is 114205512120143. The reversal of 114205512120135 is 531021215502411.
It is not a de Polignac number, because 114205512120135 - 224 = 114205495342919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114205512120096 and 114205512120105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8496795015 + ... + 8496808455.
It is an arithmetic number, because the mean of its divisors is an integer number (2878066620000).
Almost surely, 2114205512120135 is an apocalyptic number.
114205512120135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114205512120135 is a deficient number, since it is larger than the sum of its proper divisors (69990751559865).
114205512120135 is a wasteful number, since it uses less digits than its factorization.
114205512120135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18296.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 114205512120135 its reverse (531021215502411), we get a palindrome (645226727622546).
The spelling of 114205512120135 in words is "one hundred fourteen trillion, two hundred five billion, five hundred twelve million, one hundred twenty thousand, one hundred thirty-five".
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