Base | Representation |
---|---|
bin | 110101001011110000… |
… | …0011100000110001011 |
3 | 101220210120011121020122 |
4 | 1222113200130012023 |
5 | 3332401004404003 |
6 | 124245014213455 |
7 | 11152153410203 |
oct | 1522740340613 |
9 | 356716147218 |
10 | 114211013003 |
11 | 4448915954a |
12 | 1a17505428b |
13 | aa01a60589 |
14 | 5756585403 |
15 | 2e86b50238 |
hex | 1a9781c18b |
114211013003 has 2 divisors, whose sum is σ = 114211013004. Its totient is φ = 114211013002.
The previous prime is 114211012987. The next prime is 114211013017. The reversal of 114211013003 is 300310112411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114211013003 - 24 = 114211012987 is a prime.
It is not a weakly prime, because it can be changed into another prime (114211013093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57105506501 + 57105506502.
It is an arithmetic number, because the mean of its divisors is an integer number (57105506502).
Almost surely, 2114211013003 is an apocalyptic number.
114211013003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114211013003 is an equidigital number, since it uses as much as digits as its factorization.
114211013003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 114211013003 its reverse (300310112411), we get a palindrome (414521125414).
The spelling of 114211013003 in words is "one hundred fourteen billion, two hundred eleven million, thirteen thousand, three".
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