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114211423234003 is a prime number
BaseRepresentation
bin11001111101111111101011…
…010011111010011111010011
3112222101111122110100120200111
4121331333223103322133103
5104432214443321442003
61042524000431302151
733025334352413134
oct3175775323723723
9488344573316614
10114211423234003
1133433879a25817
1210986b3267a957
134b96124bcb404
14202bc10523c8b
15d30d7b933e6d
hex67dfeb4fa7d3

114211423234003 has 2 divisors, whose sum is σ = 114211423234004. Its totient is φ = 114211423234002.

The previous prime is 114211423234001. The next prime is 114211423234109. The reversal of 114211423234003 is 300432324112411.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114211423234003 - 21 = 114211423234001 is a prime.

Together with 114211423234001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (114211423234001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57105711617001 + 57105711617002.

It is an arithmetic number, because the mean of its divisors is an integer number (57105711617002).

Almost surely, 2114211423234003 is an apocalyptic number.

114211423234003 is a deficient number, since it is larger than the sum of its proper divisors (1).

114211423234003 is an equidigital number, since it uses as much as digits as its factorization.

114211423234003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 114211423234003 its reverse (300432324112411), we get a palindrome (414643747346414).

The spelling of 114211423234003 in words is "one hundred fourteen trillion, two hundred eleven billion, four hundred twenty-three million, two hundred thirty-four thousand, three".