Base | Representation |
---|---|
bin | 11001111101111111101011… |
… | …010011111010011111010011 |
3 | 112222101111122110100120200111 |
4 | 121331333223103322133103 |
5 | 104432214443321442003 |
6 | 1042524000431302151 |
7 | 33025334352413134 |
oct | 3175775323723723 |
9 | 488344573316614 |
10 | 114211423234003 |
11 | 33433879a25817 |
12 | 10986b3267a957 |
13 | 4b96124bcb404 |
14 | 202bc10523c8b |
15 | d30d7b933e6d |
hex | 67dfeb4fa7d3 |
114211423234003 has 2 divisors, whose sum is σ = 114211423234004. Its totient is φ = 114211423234002.
The previous prime is 114211423234001. The next prime is 114211423234109. The reversal of 114211423234003 is 300432324112411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114211423234003 - 21 = 114211423234001 is a prime.
Together with 114211423234001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (114211423234001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57105711617001 + 57105711617002.
It is an arithmetic number, because the mean of its divisors is an integer number (57105711617002).
Almost surely, 2114211423234003 is an apocalyptic number.
114211423234003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114211423234003 is an equidigital number, since it uses as much as digits as its factorization.
114211423234003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 114211423234003 its reverse (300432324112411), we get a palindrome (414643747346414).
The spelling of 114211423234003 in words is "one hundred fourteen trillion, two hundred eleven billion, four hundred twenty-three million, two hundred thirty-four thousand, three".
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