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114223120151341 is a prime number
BaseRepresentation
bin11001111110001010100100…
…100000000111001100101101
3112222102121211122011112210011
4121332022210200013030231
5104432412422224320331
61042533213233013221
733026230253521015
oct3176124440071455
9488377748145704
10114223120151341
1133438831597953
12109892579b4211
134b9726a325c86
14202c5ddba8c45
15d313137873b1
hex67e2a480732d

114223120151341 has 2 divisors, whose sum is σ = 114223120151342. Its totient is φ = 114223120151340.

The previous prime is 114223120151339. The next prime is 114223120151411. The reversal of 114223120151341 is 143151021322411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106822250185225 + 7400869966116 = 10335485^2 + 2720454^2 .

It is a cyclic number.

It is not a de Polignac number, because 114223120151341 - 21 = 114223120151339 is a prime.

Together with 114223120151339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114223120151311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57111560075670 + 57111560075671.

It is an arithmetic number, because the mean of its divisors is an integer number (57111560075671).

Almost surely, 2114223120151341 is an apocalyptic number.

It is an amenable number.

114223120151341 is a deficient number, since it is larger than the sum of its proper divisors (1).

114223120151341 is an equidigital number, since it uses as much as digits as its factorization.

114223120151341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 114223120151341 its reverse (143151021322411), we get a palindrome (257374141473752).

The spelling of 114223120151341 in words is "one hundred fourteen trillion, two hundred twenty-three billion, one hundred twenty million, one hundred fifty-one thousand, three hundred forty-one".