Base | Representation |
---|---|
bin | 11001111110010010000111… |
… | …111001001010010110000011 |
3 | 112222110101202211111021221020 |
4 | 121332102013321022112003 |
5 | 104433031024402110110 |
6 | 1042541034101400523 |
7 | 33026635241203401 |
oct | 3176220771122603 |
9 | 488411684437836 |
10 | 114231230113155 |
11 | 33441213440231 |
12 | 1098a93ba09143 |
13 | 4b97c60589c4c |
14 | 202cb6ccd8471 |
15 | d3163a753d70 |
hex | 67e487e4a583 |
114231230113155 has 64 divisors (see below), whose sum is σ = 184445771328000. Its totient is φ = 60366796574720.
The previous prime is 114231230113141. The next prime is 114231230113229. The reversal of 114231230113155 is 551311032132411.
It is not a de Polignac number, because 114231230113155 - 232 = 114226935145859 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3944297875 + ... + 3944326835.
It is an arithmetic number, because the mean of its divisors is an integer number (2881965177000).
Almost surely, 2114231230113155 is an apocalyptic number.
114231230113155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114231230113155 is a deficient number, since it is larger than the sum of its proper divisors (70214541214845).
114231230113155 is a wasteful number, since it uses less digits than its factorization.
114231230113155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33364.
The product of its (nonzero) digits is 10800, while the sum is 33.
Adding to 114231230113155 its reverse (551311032132411), we get a palindrome (665542262245566).
The spelling of 114231230113155 in words is "one hundred fourteen trillion, two hundred thirty-one billion, two hundred thirty million, one hundred thirteen thousand, one hundred fifty-five".
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