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114235312127 is a prime number
BaseRepresentation
bin110101001100011110…
…1001000011111111111
3101220212020220010101012
41222120331020133333
53332423214442002
6124251243105435
711152600063136
oct1523075103777
9356766803335
10114235312127
11444a0945872
121a18121227b
13aa06aba761
1457598ac91d
152e88d4ed52
hex1a98f487ff

114235312127 has 2 divisors, whose sum is σ = 114235312128. Its totient is φ = 114235312126.

The previous prime is 114235312117. The next prime is 114235312223. The reversal of 114235312127 is 721213532411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114235312127 - 210 = 114235311103 is a prime.

It is a super-2 number, since 2×1142353121272 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114235312093 and 114235312102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114235312117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57117656063 + 57117656064.

It is an arithmetic number, because the mean of its divisors is an integer number (57117656064).

Almost surely, 2114235312127 is an apocalyptic number.

114235312127 is a deficient number, since it is larger than the sum of its proper divisors (1).

114235312127 is an equidigital number, since it uses as much as digits as its factorization.

114235312127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10080, while the sum is 32.

Adding to 114235312127 its reverse (721213532411), we get a palindrome (835448844538).

The spelling of 114235312127 in words is "one hundred fourteen billion, two hundred thirty-five million, three hundred twelve thousand, one hundred twenty-seven".