11424000031 has 2 divisors, whose sum is σ = 11424000032. Its totient is φ = 11424000030.

The previous prime is 11424000013. The next prime is 11424000041. The reversal of 11424000031 is 13000042411.

11424000031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11424000013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11424000031 - 2⁹ = 11423999519 is a prime.

It is a super-2 number, since 2×11424000031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11423999969 and 11424000014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11424000041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712000015 + 5712000016.

It is an arithmetic number, because the mean of its divisors is an integer number (5712000016).

Almost surely, 2^11424000031 is an apocalyptic number.

11424000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11424000031 is an equidigital number, since it uses as much as digits as its factorization.

11424000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 11424000031 its reverse (13000042411), we get a palindrome (24424042442).

The spelling of 11424000031 in words is "eleven billion, four hundred twenty-four million, thirty-one", and thus it is an aban number.