11424000113 has 2 divisors, whose sum is σ = 11424000114. Its totient is φ = 11424000112.

The previous prime is 11424000101. The next prime is 11424000149. The reversal of 11424000113 is 31100042411.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5976526864 + 5447473249 = 77308^2 + 73807^2 .

It is a cyclic number.

It is not a de Polignac number, because 11424000113 - 2¹⁰ = 11423999089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11424000091 and 11424000100.

It is not a weakly prime, because it can be changed into another prime (11424000193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712000056 + 5712000057.

It is an arithmetic number, because the mean of its divisors is an integer number (5712000057).

Almost surely, 2^11424000113 is an apocalyptic number.

It is an amenable number.

11424000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11424000113 is an equidigital number, since it uses as much as digits as its factorization.

11424000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11424000113 its reverse (31100042411), we get a palindrome (42524042524).

The spelling of 11424000113 in words is "eleven billion, four hundred twenty-four million, one hundred thirteen", and thus it is an aban number.