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114240132514142 = 257120066257071
BaseRepresentation
bin11001111110011010011010…
…100001001000000101011110
3112222111020202020221010021022
4121332122122201020011132
5104433202242410423032
61042545105315004142
733030401660312255
oct3176323241100536
9488436666833238
10114240132514142
1133444a7162a918
1210990605299652
134b98a4ba5753b
14202d37538579c
15d319ac0a2512
hex67e69a84815e

114240132514142 has 4 divisors (see below), whose sum is σ = 171360198771216. Its totient is φ = 57120066257070.

The previous prime is 114240132514127. The next prime is 114240132514169. The reversal of 114240132514142 is 241415231042411.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28560033128534 + ... + 28560033128537.

It is an arithmetic number, because the mean of its divisors is an integer number (42840049692804).

Almost surely, 2114240132514142 is an apocalyptic number.

114240132514142 is a deficient number, since it is larger than the sum of its proper divisors (57120066257074).

114240132514142 is an equidigital number, since it uses as much as digits as its factorization.

114240132514142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57120066257073.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 114240132514142 its reverse (241415231042411), we get a palindrome (355655363556553).

The spelling of 114240132514142 in words is "one hundred fourteen trillion, two hundred forty billion, one hundred thirty-two million, five hundred fourteen thousand, one hundred forty-two".

Divisors: 1 2 57120066257071 114240132514142