Base | Representation |
---|---|
bin | 1010011000111101110001… |
… | …0100001111000110001111 |
3 | 1111110010101012102112020011 |
4 | 2212033130110033012033 |
5 | 2444132340132113203 |
6 | 40144041510134051 |
7 | 2256233503430056 |
oct | 246173424170617 |
9 | 44403335375204 |
10 | 11424014332303 |
11 | 37049962a3631 |
12 | 1346073351327 |
13 | 64b384009181 |
14 | 2b6cd4c2539d |
15 | 14c27147576d |
hex | a63dc50f18f |
11424014332303 has 2 divisors, whose sum is σ = 11424014332304. Its totient is φ = 11424014332302.
The previous prime is 11424014332277. The next prime is 11424014332307. The reversal of 11424014332303 is 30323341042411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11424014332303 - 29 = 11424014331791 is a prime.
It is a super-3 number, since 3×114240143323033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11424014332307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5712007166151 + 5712007166152.
It is an arithmetic number, because the mean of its divisors is an integer number (5712007166152).
Almost surely, 211424014332303 is an apocalyptic number.
11424014332303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11424014332303 is an equidigital number, since it uses as much as digits as its factorization.
11424014332303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 11424014332303 its reverse (30323341042411), we get a palindrome (41747355374714).
The spelling of 11424014332303 in words is "eleven trillion, four hundred twenty-four billion, fourteen million, three hundred thirty-two thousand, three hundred three".
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