Base | Representation |
---|---|
bin | 11001111110011010011111… |
… | …010100010110001101011111 |
3 | 112222111020221212110202222112 |
4 | 121332122133110112031133 |
5 | 104433202424020101312 |
6 | 1042545121313104235 |
7 | 33030403656000266 |
oct | 3176323724261537 |
9 | 488436855422875 |
10 | 114240213050207 |
11 | 33445003037852 |
12 | 1099062825807b |
13 | 4b98a6264490a |
14 | 202d381d4b5dd |
15 | d319b41aed22 |
hex | 67e69f51635f |
114240213050207 has 2 divisors, whose sum is σ = 114240213050208. Its totient is φ = 114240213050206.
The previous prime is 114240213050189. The next prime is 114240213050347. The reversal of 114240213050207 is 702050312042411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114240213050207 - 216 = 114240212984671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114240213059207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120106525103 + 57120106525104.
It is an arithmetic number, because the mean of its divisors is an integer number (57120106525104).
Almost surely, 2114240213050207 is an apocalyptic number.
114240213050207 is a deficient number, since it is larger than the sum of its proper divisors (1).
114240213050207 is an equidigital number, since it uses as much as digits as its factorization.
114240213050207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
Adding to 114240213050207 its reverse (702050312042411), we get a palindrome (816290525092618).
The spelling of 114240213050207 in words is "one hundred fourteen trillion, two hundred forty billion, two hundred thirteen million, fifty thousand, two hundred seven".
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