Base | Representation |
---|---|
bin | 11001111110011011010001… |
… | …010010001110010010111111 |
3 | 112222111100010021220001000101 |
4 | 121332123101102032102333 |
5 | 104433211133121314203 |
6 | 1042545340420541531 |
7 | 33030433515316456 |
oct | 3176332122162277 |
9 | 488440107801011 |
10 | 114241051354303 |
11 | 334453a3260055 |
12 | 10990820b518a7 |
13 | 4b98b67219443 |
14 | 202d421407b9d |
15 | d31a12aa141d |
hex | 67e6d148e4bf |
114241051354303 has 2 divisors, whose sum is σ = 114241051354304. Its totient is φ = 114241051354302.
The previous prime is 114241051354291. The next prime is 114241051354369. The reversal of 114241051354303 is 303453150142411.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114241051354303 - 237 = 114103612400831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114241051354373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120525677151 + 57120525677152.
It is an arithmetic number, because the mean of its divisors is an integer number (57120525677152).
Almost surely, 2114241051354303 is an apocalyptic number.
114241051354303 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241051354303 is an equidigital number, since it uses as much as digits as its factorization.
114241051354303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 114241051354303 in words is "one hundred fourteen trillion, two hundred forty-one billion, fifty-one million, three hundred fifty-four thousand, three hundred three".
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