Base | Representation |
---|---|
bin | 110101001100101001… |
… | …1010010011100000011 |
3 | 101220212122211012021201 |
4 | 1222121103102130003 |
5 | 3332431211320003 |
6 | 124252011402031 |
7 | 11153000332543 |
oct | 1523123223403 |
9 | 356778735251 |
10 | 114241120003 |
11 | 444a415236a |
12 | 1a183153317 |
13 | aa0807217a |
14 | 575a581323 |
15 | 2e895eab1d |
hex | 1a994d2703 |
114241120003 has 2 divisors, whose sum is σ = 114241120004. Its totient is φ = 114241120002.
The previous prime is 114241119997. The next prime is 114241120009. The reversal of 114241120003 is 300021142411.
It is a balanced prime because it is at equal distance from previous prime (114241119997) and next prime (114241120009).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114241120003 is a prime.
It is not a weakly prime, because it can be changed into another prime (114241120009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120560001 + 57120560002.
It is an arithmetic number, because the mean of its divisors is an integer number (57120560002).
Almost surely, 2114241120003 is an apocalyptic number.
114241120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114241120003 is an equidigital number, since it uses as much as digits as its factorization.
114241120003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 114241120003 its reverse (300021142411), we get a palindrome (414262262414).
The spelling of 114241120003 in words is "one hundred fourteen billion, two hundred forty-one million, one hundred twenty thousand, three".
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