Base | Representation |
---|---|
bin | 11001111110011011010110… |
… | …000011100111111101000000 |
3 | 112222111100022212112110022212 |
4 | 121332123112003213331000 |
5 | 104433211314120211222 |
6 | 1042545352400521252 |
7 | 33030435506646611 |
oct | 3176332603477500 |
9 | 488440285473285 |
10 | 114241131413312 |
11 | 33445434471622 |
12 | 10990843920228 |
13 | 4b98b7a99a637 |
14 | 202d42bcc7c08 |
15 | d31a19b176e2 |
hex | 67e6d60e7f40 |
114241131413312 has 56 divisors (see below), whose sum is σ = 236904790843776. Its totient is φ = 54605112726528.
The previous prime is 114241131413309. The next prime is 114241131413369. The reversal of 114241131413312 is 213314131142411.
It is a super-2 number, since 2×1142411314133122 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441488093 + ... + 441746780.
Almost surely, 2114241131413312 is an apocalyptic number.
It is an amenable number.
114241131413312 is an abundant number, since it is smaller than the sum of its proper divisors (122663659430464).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114241131413312 is an equidigital number, since it uses as much as digits as its factorization.
114241131413312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 883234975 (or 883234965 counting only the distinct ones).
The product of its digits is 6912, while the sum is 32.
Adding to 114241131413312 its reverse (213314131142411), we get a palindrome (327555262555723).
The spelling of 114241131413312 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred thirty-one million, four hundred thirteen thousand, three hundred twelve".
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