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114241252125311 is a prime number
BaseRepresentation
bin11001111110011011011101…
…010000000110101001111111
3112222111100122021200021001122
4121332123131100012221333
5104433212041021002221
61042545412352101155
733030441503664623
oct3176333520065177
9488440567607048
10114241252125311
113344549661a303
12109908782347bb
134b98b999b365c
14202d43dd4b183
15d31a2550deab
hex67e6dd406a7f

114241252125311 has 2 divisors, whose sum is σ = 114241252125312. Its totient is φ = 114241252125310.

The previous prime is 114241252125289. The next prime is 114241252125313. The reversal of 114241252125311 is 113521252142411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114241252125311 - 210 = 114241252124287 is a prime.

Together with 114241252125313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114241252125313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57120626062655 + 57120626062656.

It is an arithmetic number, because the mean of its divisors is an integer number (57120626062656).

Almost surely, 2114241252125311 is an apocalyptic number.

114241252125311 is a deficient number, since it is larger than the sum of its proper divisors (1).

114241252125311 is an equidigital number, since it uses as much as digits as its factorization.

114241252125311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19200, while the sum is 35.

The spelling of 114241252125311 in words is "one hundred fourteen trillion, two hundred forty-one billion, two hundred fifty-two million, one hundred twenty-five thousand, three hundred eleven".