Base | Representation |
---|---|
bin | 11001111110101000010000… |
… | …110100100100101000000011 |
3 | 112222112200010112220201001211 |
4 | 121332220100310210220003 |
5 | 104433423221032201110 |
6 | 1043000005020310551 |
7 | 33031436315625361 |
oct | 3176502064445003 |
9 | 488480115821054 |
10 | 114255002225155 |
11 | 33450302152890 |
12 | 109934750a2457 |
13 | 4b9a27b5b63cc |
14 | 202dd86172631 |
15 | d3207c72c98a |
hex | 67ea10d24a03 |
114255002225155 has 64 divisors (see below), whose sum is σ = 158686587924480. Its totient is φ = 78099327446400.
The previous prime is 114255002225113. The next prime is 114255002225167. The reversal of 114255002225155 is 551522200552411.
It is not a de Polignac number, because 114255002225155 - 217 = 114255002094083 is a prime.
It is a super-3 number, since 3×1142550022251553 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 520501954 + ... + 520721416.
It is an arithmetic number, because the mean of its divisors is an integer number (2479477936320).
Almost surely, 2114255002225155 is an apocalyptic number.
114255002225155 is a deficient number, since it is larger than the sum of its proper divisors (44431585699325).
114255002225155 is a wasteful number, since it uses less digits than its factorization.
114255002225155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223432.
The product of its (nonzero) digits is 200000, while the sum is 40.
Adding to 114255002225155 its reverse (551522200552411), we get a palindrome (665777202777566).
The spelling of 114255002225155 in words is "one hundred fourteen trillion, two hundred fifty-five billion, two million, two hundred twenty-five thousand, one hundred fifty-five".
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