Base | Representation |
---|---|
bin | 11001111110101000010010… |
… | …100011011111100100110111 |
3 | 112222112200012120121222121212 |
4 | 121332220102203133210313 |
5 | 104433423301003134310 |
6 | 1043000011535432035 |
7 | 33031440121032011 |
oct | 3176502243374467 |
9 | 488480176558555 |
10 | 114255031302455 |
11 | 3345031760300a |
12 | 1099348298561b |
13 | 4b9a284627404 |
14 | 202dd89d811b1 |
15 | d32080073205 |
hex | 67ea128df937 |
114255031302455 has 8 divisors (see below), whose sum is σ = 137947178898672. Its totient is φ = 90843264151488.
The previous prime is 114255031302449. The next prime is 114255031302463. The reversal of 114255031302455 is 554203130552411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114255031302455 - 210 = 114255031301431 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70095110414 + ... + 70095112043.
It is an arithmetic number, because the mean of its divisors is an integer number (17243397362334).
Almost surely, 2114255031302455 is an apocalyptic number.
114255031302455 is a deficient number, since it is larger than the sum of its proper divisors (23692147596217).
114255031302455 is a wasteful number, since it uses less digits than its factorization.
114255031302455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140190222625.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 114255031302455 its reverse (554203130552411), we get a palindrome (668458161854866).
The spelling of 114255031302455 in words is "one hundred fourteen trillion, two hundred fifty-five billion, thirty-one million, three hundred two thousand, four hundred fifty-five".
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