Base | Representation |
---|---|
bin | 11001111110101000010110… |
… | …101011000101011010100111 |
3 | 112222112200101101122120110001 |
4 | 121332220112223011122213 |
5 | 104433423421200320234 |
6 | 1043000022444442131 |
7 | 33031441620253303 |
oct | 3176502653053247 |
9 | 488480341576401 |
10 | 114255100401319 |
11 | 33450352609009 |
12 | 109934a1b49347 |
13 | 4b9a295a3ba07 |
14 | 202dd9520ad03 |
15 | d32086171d14 |
hex | 67ea16ac56a7 |
114255100401319 has 2 divisors, whose sum is σ = 114255100401320. Its totient is φ = 114255100401318.
The previous prime is 114255100401301. The next prime is 114255100401467. The reversal of 114255100401319 is 913104001552411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114255100401319 - 213 = 114255100393127 is a prime.
It is a super-2 number, since 2×1142551004013192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114255100491319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127550200659 + 57127550200660.
It is an arithmetic number, because the mean of its divisors is an integer number (57127550200660).
Almost surely, 2114255100401319 is an apocalyptic number.
114255100401319 is a deficient number, since it is larger than the sum of its proper divisors (1).
114255100401319 is an equidigital number, since it uses as much as digits as its factorization.
114255100401319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 37.
The spelling of 114255100401319 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred million, four hundred one thousand, three hundred nineteen".
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