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114255100401319 is a prime number
BaseRepresentation
bin11001111110101000010110…
…101011000101011010100111
3112222112200101101122120110001
4121332220112223011122213
5104433423421200320234
61043000022444442131
733031441620253303
oct3176502653053247
9488480341576401
10114255100401319
1133450352609009
12109934a1b49347
134b9a295a3ba07
14202dd9520ad03
15d32086171d14
hex67ea16ac56a7

114255100401319 has 2 divisors, whose sum is σ = 114255100401320. Its totient is φ = 114255100401318.

The previous prime is 114255100401301. The next prime is 114255100401467. The reversal of 114255100401319 is 913104001552411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114255100401319 - 213 = 114255100393127 is a prime.

It is a super-2 number, since 2×1142551004013192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114255100491319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127550200659 + 57127550200660.

It is an arithmetic number, because the mean of its divisors is an integer number (57127550200660).

Almost surely, 2114255100401319 is an apocalyptic number.

114255100401319 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255100401319 is an equidigital number, since it uses as much as digits as its factorization.

114255100401319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 37.

The spelling of 114255100401319 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred million, four hundred one thousand, three hundred nineteen".