114255100401467 has 2 divisors, whose sum is σ = 114255100401468. Its totient is φ = 114255100401466.

The previous prime is 114255100401319. The next prime is 114255100401469. The reversal of 114255100401467 is 764104001552411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114255100401467 - 2³⁴ = 114237920532283 is a prime.

Together with 114255100401469, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114255100401469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57127550200733 + 57127550200734.

It is an arithmetic number, because the mean of its divisors is an integer number (57127550200734).

Almost surely, 2^{114255100401467} is an apocalyptic number.

114255100401467 is a deficient number, since it is larger than the sum of its proper divisors (1).

114255100401467 is an equidigital number, since it uses as much as digits as its factorization.

114255100401467 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 41.

Adding to 114255100401467 its reverse (764104001552411), we get a palindrome (878359101953878).

The spelling of 114255100401467 in words is "one hundred fourteen trillion, two hundred fifty-five billion, one hundred million, four hundred one thousand, four hundred sixty-seven".